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A block of mass 10kg is placed on rough inclined plasne of variable angle `theta` and friction coefficient `mu_(s)=mu_(k)=3//4`. When `theta` is `37^(@)` net reaction force applied by inclined is `vecN_(1)` and when `theta = 53^(@)` net reaction force applied by inclined is `vecN_(2)` , then `|vecN_(1)|-|vecN_(2)|` is :A. `0`B. `25N`C. `-25N`D. `-37N` |
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Answer» Correct Answer - B A block of ………….. `Mg - sqrt(1+mu^(2))Mg cos theta` `= 25 N`. |
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