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A block of mass 2 kg is placed on the floor . The coefficient of static friction is `0.4` . If a force of `2.8` N is applied on the block parallel to floor , the force of friction between the block and floor is : (Taking g = `10 m//s^(2)`)A. 2.8NB. 8NC. 2.0ND. zero |
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Answer» Correct Answer - A `f_("max")=20xx0.4=8N` `therefore f=2.8N` |
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