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A block of mass 25 kg is raised by a 50 kg man in two different ways as shown in Fig.5.19. What is the action on the floor by the man in the two cases? If the floor yields to a normal force of 700 N, which mode should the man adopt to lift the block without the floor yielding? |
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Answer» 750 N and 250 N in the respective cases; Method (b) Mass of the block, m = 25 kg Mass of the man, M = 50 kg Acceleration due to gravity, g = 10 m/s2 Force applied on the block, F = 25 × 10 = 250 N Weight of the man, W = 50 × 10 = 500 N Case (a): When the man lifts the block directly In this case, the man applies a force in the upward direction. This increases his apparent weight. Action on the floor by the man = 250 + 500 = 750 N Case (b): When the man lifts the block using a pulley In this case, the man applies a force in the downward direction. This decreases his apparent weight. Action on the floor by the man = 500 – 250 = 250 N If the floor can yield to a normal force of 700 N, then the man should adopt the second method to easily lift the block by applying lesser force. |
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