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A block of mass 25 kg is raised by a 50 kg man in two different ways as shown in Fig.5.19. What is the action on the floor by the man in the two cases? If the floor yields to a normal force of 700 N, which mode should the man adopt to lift the block without the floor yielding? |
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Answer» 750 N and 250 N in the respective cases; Method (b) Force applied on the block, F = 25 × 10 = 250 N In this case, the man applies a force in the upward direction. This increases his apparent weight. Action on the floor by the man = 250 + 500 = 750 N Action on the floor by the man = 500 – 250 = 250 N |
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