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A block of mass 25 kg is raised by a 50 kg man in two different ways as shown in Fig. What is the action on the floor by the man in the two cases? If the floor yields to a normal force of 700 N, which mode should the man adopt to lift the block without the floor yielding? |
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Answer» In the first case man applies an upward force of 25 kg weight. Hence the action on the floor by man is = 50 kg weight + 25 kg weight = 75 kg weight = 75 × 10 = 750 N. In the second case man applies a downward force of 25 kg weight. Hence the action on the floor by man is = 50 kg weight – 25 kg weight = 25 × 10 = 250 N. (Other 500 N is applied on the ceiling) Hence man should adopt the second case. |
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