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A block of mass `2kg` is attached with a spring of spring constant `4000Nm^-1` and the system is kept on smooth horizontal table. The other end of the spring is attached with a wall. Initially spring is stretched by `5cm` from its natural position and the block is at rest. Now suddenly an impulse of `4kg-ms^-1` is given to the block towards the wall. Find the velocity of the block when spring acquires its natural lengthA. (a) `5ms^-1`B. (b) `3ms^-1`C. (c) `6ms^-1`D. (d) None of these |
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Answer» Correct Answer - B `Impu lse=m u` `:. u=("Impulse")/(m)=`4/2=2m//s` Now, `E_i=E_f` `:. 1/2xx2xx(2)^2+1/2xx4000xx(0.05)^2` `=1/2xx2xxv^2` Solving we get, `v=3m//s` |
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