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A block of mass 3kg is placed on a rough horizontal surface `(mu_(s)=0.4)` . A forc eof `8.7N` is applied on th eblock. The force of friction between the block and floor is .A. `8.7N`B. 12NC. 10ND. zero |
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Answer» Correct Answer - A `f_(ms)=mu_(s)mg=0.4xx3xx10N=12N` Since the applied force is less than `12N` therefore the force of friction is equal to the applied force. `f=8.7N` . |
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