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A block of mass 4 kg is kept on ground. The co-efficient of friction between the block and the ground is 0.80. an external force of magnitude 30 N is applied parallel to the ground. The resultant force exerted by the ground on the block is `(g=10m//x^(2))`A. 40NB. 30NC. 0ND. 50N |
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Answer» Correct Answer - D N=mg=40 `(f_(s))_(max)=muN=(0.8) (40)=32` `f_(S)=ext` force =30 `R^(2)=N^(2)+f_(s)^(2)=(50)^(2)` `:. R=50 Nt`. |
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