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A block of mass `4 kg` slides on a horizontal frictionless surface with a speed of `2m//s`. It is brought to rest in compressing a spring in its path. If the force constant of the spring is `400 N//m`, by how much the spring will be compressedA. `2 xx 10^(-2)m`B. `0.2 m`C. `20m`D. `200 m` |
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Answer» Correct Answer - B `K.E.` of block is converted into elastic `P.E.` in spring i.e., `(1)/(2) mv^(2) = (1)/(2)k x^(2)` |
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