A block of mass 5 kg is kept on a horizontal floor having coefficient of friction 0.09. Two mutually perpendicular horizontal forces of 3 N and 4 N this block. The accelation of the block is ( take, g=10 ms^(-2))

A block of mass 5 kg is kept on a horizontal floor having coefficient

1.	A block of mass 5 kg is kept on a horizontal floor having coefficient of friction 0.09. Two mutually perpendicular horizontal forces of 3 N and 4 N this block. The accelation of the block is ( take, g=10 ms^(-2))
Answer» zero `0.1 ms^(-2)` `0.2 ms^(-2)` `0.3 ms^(-2)` Solution :(b) Net external FORCE, F`=sqrt((4)^(2)+(3)^(2))=5N` Maximum friction `f_("max")=mu mg` Since `F GT f_("max")` block will MOVE with an acceleration, `a=(F-f_("max"))/(m)` `=(5-4.5)/(5)=0.1 ms^(-2)`