Saved Bookmarks
| 1. |
A block of mass 5 kg resting on a horizontal surface is connected by a cord, passing over a light frictionless pulley to a hanging block of mass 5 kg. The coefficient of kinetic friction between the block and surface is 0.5. Tension in the cord is (take, g=9.8ms^(-2)) |
|
Answer» 49 N `=(5g-0.5xx5xxg)/(10)=(g)/(4)` Equation of motion for the hanging mass will be, `5g-T=5a=(5g)/(4)` `THEREFORE"" T=(15)/(4)g=(15xx9.8)/(4)=36.75 N` |
|