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A block of mass 50 kg slides over a horizontal distance of 1m. If the coefficient of friction between their surface is 0.2, then work done against friction is (take `g = 9.8 m//s^(2)`) :A. 98 JB. 72 JC. 56 JD. 34 J |
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Answer» Correct Answer - A `W=mu mg S=0.2 xx 50 xx 9.8 xx 1=98 J` |
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