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A block of mass m=0.5 kg is released from the top of a wedge of mass M=9.5 kg as shown in the figure. The inclination angle of the wedge is θ=45∘ and its height is h=2 m. The displacement of the wedge on the horizontal ground, when the block reaches the bottom of the wedge, is (Neglect friction everywhere.)

Answer» A block of mass m=0.5 kg is released from the top of a wedge of mass M=9.5 kg as shown in the figure. The inclination angle of the wedge is θ=45 and its height is h=2 m. The displacement of the wedge on the horizontal ground, when the block reaches the bottom of the wedge, is (Neglect friction everywhere.)






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