A block of mass m=20 kg is kept at a distance R=1m from the central axis of rotation of a round turn table (a table whose surface can rotate about the central axis). Table starts from rest and rotates with constant angular acceleration, α=3 rad/sec2. The friction coefficient between the block and the table is μ=0.5. At time t=x30 from the starting of the motion (i.e. t=0), the block is just about to slip. The value of x is (g=10ms−2)

A block of mass m=20 kg is kept at a distance R=1m from the central ax

1.	A block of mass m=20 kg is kept at a distance R=1m from the central axis of rotation of a round turn table (a table whose surface can rotate about the central axis). Table starts from rest and rotates with constant angular acceleration, α=3 rad/sec2. The friction coefficient between the block and the table is μ=0.5. At time t=x30 from the starting of the motion (i.e. t=0), the block is just about to slip. The value of x is (g=10ms−2)
Answer» A block of mass $m = 20 k g$ is kept at a distance $R = 1 m$ from the central axis of rotation of a round turn table (a table whose surface can rotate about the central axis). Table starts from rest and rotates with constant angular acceleration, $α = 3 r a d / s e c^{2}$ . The friction coefficient between the block and the table is $μ = 0.5$ . At time $t = \frac{x}{30}$ from the starting of the motion (i.e. $t = 0$ ), the block is just about to slip. The value of $x$ is ( $g = 10 m s^{- 2}$ )

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