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A block of mass `m=2kg` is placed in equilibrium on a moving plank accelerating with `a=1m//s^(2)` . If coefficient of friction between plank and block `mu=0.2` . The friction force acting on theblock is:A. 2NB. 4NC. 3ND. None of these |
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Answer» Correct Answer - A In this case driving force=ma `=2xx1=2N` And resisting force `=f_(lim)=muN=4N` Hence the mass will not slide over the plank friction should be static nature `f=2N` . |
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