1.

A block of mass m be placed on a frictionless surface of a table. Springconstants of a spring joint on both side are k_(1)" and "k_(2) if block. Leave the block by slight displaced it, then its angular frequency will be……….

Answer»

`((k_(1)+k_(2))/(m))^(1/2)`
`((k_(1)k_(2))/(m(k_(1)+k_(2))))^(1/2)`
`((k_(1)k_(2))/((k_(1)-k_(2))m))^(1/2)`
`((k_(1)^(2)+k_(2)^(2))/((k_(1)+k_(2))m))^(1/2)`

SOLUTION :Here, spring are PARALLEL HENCE `k_(eq)= k_(1)+ k_(2)`
and `omega = sqrt((k_(eq))/(m))= ((k_(1)+k_(2))/(m))^(1/2)`.


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