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A block of mass m & charge q is released on a long smooth inclined plane magnetic field `B` is constant, unifrom, horizontal and parallel to surface a shown Find the time from start when block loses contact with the surface .A. `(m costheta)/(qB)`B. `(mcosectheta)/(qB)`C. `(mcottheta)/(qB)`D. none |
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Answer» Correct Answer - C Block will loses confact when force due to magnetic field will become equal to mag costheta `qVB = mg cos theta` `V = (mg costheta)/(qB) = g sinthetat = (m cottheta)/(qB)` . |
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