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A block of mass 'm' is attached to the light spring of force constant k and released when it is in its natural length. Find amplitude of subsequent oscillations, |
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Answer» Solution :The MAXIMUM DISPLACEMENT of the spring in subsequent MOTION will be `(2mg)/(k)`The equilibrium POSITION of the system will occur at the extension of `(mg)/(k)` `:. "amplitude"= (2mg)/(k)-(mg)/(k)= (mg)/(k)` |
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