A block of mass m is given an initial downward velocity v_(0) and left on inclined place ( coefficient of friction =0.6). The block will

A block of mass m is given an initial downward velocity v_(0) and left

1.	A block of mass m is given an initial downward velocity v_(0) and left on inclined place ( coefficient of friction =0.6). The block will
Answer» continue of move down the plane with constant velocity `v_(0)` accelerate downward decelerate and COME to rest first accelerate downward then decelerate Solution :( c) `f_("MAX")=mu mg COS thet=0.6xxmgxx(sqrt(3))/(2)=0.52 mg ` SINCE ,`f_("max")gt mg sin theta` Block will decelerate and come to rest.