A block of mass m is kept on an inclined plane of a lift moving down with acceleration of 2 ms^(-1).What should be the coefficient of friction to let the block move down with constant velocity relative to lift.

A block of mass m is kept on an inclined plane of a lift moving down w

1.	A block of mass m is kept on an inclined plane of a lift moving down with acceleration of 2 ms^(-1).What should be the coefficient of friction to let the block move down with constant velocity relative to lift.
Answer» `MU=(1)/(SQRT(3))` `mu=0.4` `mu=0.8` `mu=(sqrt(3))/(2)` Solution :(a) `m(g-a)sin theta=mu m(g-a)COS theta` LT brgt `implies"" mu=tan theta=tan 30^(@)=(1)/(sqrt(3))`