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A block of mass m is placed on a circular track and then it is given a velocity `upsilon` vertically downwards at position A on track. If block moves on track with constant speed, then A. Coefficient of friction between block and circular track as function of angle `theta` is `mu=(sintheta)/(cottheta+v^(2)/(Rg))`B. Coefficient of friction between block and circular track as function of angle `theta` is `mu=(sintheta)/(costheta+v^(2)/(Rg))`C. Instantaneous power due to friction is `-mgv sin theta`D. Work done from A to C by friction on block will be `-mgR` |
Answer» Correct Answer - B::C::D |
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