1.

A block of mass m is placed on a circular track and then it is given a velocity `upsilon` vertically downwards at position A on track. If block moves on track with constant speed, then A. Coefficient of friction between block and circular track as function of angle `theta` is `mu=(sintheta)/(cottheta+v^(2)/(Rg))`B. Coefficient of friction between block and circular track as function of angle `theta` is `mu=(sintheta)/(costheta+v^(2)/(Rg))`C. Instantaneous power due to friction is `-mgv sin theta`D. Work done from A to C by friction on block will be `-mgR`

Answer» Correct Answer - B::C::D


Discussion

No Comment Found

Related InterviewSolutions