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A block of mass `M` is pulled along a horizontal frictionless surface by a rope of mass `m` . Force P is applied at one end of rope. The force which the rope exerts on the block is:A. F/(M+m)B. F should be equal to the weight of A and BC. FM/(m+M)D. Zero |
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Answer» Correct Answer - C `a=(F)/(M+m)` Force on `M=Mxx(F)/(M+m)` |
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