1.

A block of mass m placed on a rough inclined plane of inclination theta = 30^@ can just be prevented from sliding down by applying a force Fi up the plane and it can be just made to slide up the plane by applying a force F_2 up the plane. If the coefficient of friction between the block and the inclined plane is (1)/( 2 sqrt(2sqrt(3)) the relation between F_1and F_2 is

Answer» <html><body><p>`F_2 =4F_1`<br/>`f_2 - 3F_1`<br/>`F_2-2F_1`<br/>`F_2 -F_1`</p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a>`F_1`requiedto preventto blockfromslidingdownis <br/> `F_1= mgsin theta- mumg cos theta ` <br/>The force` F_2`requiedto maketheblock moveupthe planeis<br/> ` F_2 = mgsintheta+ mu <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> cos theta` <br/>adding(i) and (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) , we get<br/> ` F_2 -F_1= 2 mu mgcostheta`<br/>` therefore(F_2+F_1)/(F_2 -F_1) = ( 2 mgsin theta)/( 2 mumgcos theta) = ( tan theta)/( mu) = (tan 30^@)/(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> // 2 sqrt(3)) =2` <br/> ` orF_2 + F_1 = 2F_2 - 2F_1 `<br/> ` or 3F_1= F_2orF_2=3F_1`</body></html>


Discussion

No Comment Found

Related InterviewSolutions