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A block of mass m slides down an inclined plane which makes an angle `theta` with the horizontal. The coefficient of friction between the block and the plane is `mu`. The force exerted by the block on the plane isA. `mg cos theta`B. `sqrt(mu^(2) + 1) mg cos theta`C. `(mumg cos theta)/(sqrt(mu^(2) + 1))`D. `mumg theta` |
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Answer» Correct Answer - B |
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