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A block of mass4 kg is pushed against a rough vertical wall with a force 80 N is applied on the block in a direction parallel to the wall . Will the block move? If yes , what is acceleration of the block ? |
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Answer» Solution :`N_(0) =80 N` `(f_(s))_(max) = mu_(s) N = 0.5 xx 80 = 40 N` `F : resultant force = SQRT((30)^(2) + (40)^(2)) = 50 N` `tan theta = (30)/(40) = (3)/(4) rArr theta = 37^(@)` The BLOCK will move when the resultant external force on it exceeds `(f_(s))_(max)`. When it moves , the direction of the force of friction will be opposite to the block's direction of motion `a = (F - (f_(s))_(max))/(m) = ( 50 - 40)/(4) = 2.5 m//s^(2)`
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