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A block of weight W rests on horizontal floor with coefficient of static friction mu. It is desired to make the block move by applying minimum amount of force. The angle thetafrom the horizontal at which the force should be applied and the magnitude F of the force is |
Answer» <html><body><p>`theta = 0,<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> = <a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a> W` <br/>`theta = tan^(-1) , F = (mu W)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(1+mu^2))` <br/>`theta = tan^(-1) (1/mu) , F = (<a href="https://interviewquestions.tuteehub.com/tag/muw-2850330" style="font-weight:bold;" target="_blank" title="Click to know more about MUW">MUW</a>)/(sqrt(1+mu^2))` <br/>`theta = tan^(-1) ((mu)/(1+mu)),F= (muW)/(1+mu^2)`</p>Answer :B</body></html> | |