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A block of wood has a mass of `25g`. When a `5g` metal piece with a volume of `2cm^(3)` is attached to the bottom of the block, the wood barely floats in water. What is the volume `V` of the wood? |
Answer» Correct Answer - B::C Weight=upthrust `:. (25+5)g=(V+2)rho_(w)g` Putting `rho_(w)=1g//cm^(3)` we get, `V=28 cm^(3)`. |
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