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| 1. |
A block released from rest from the top of a smooth inclined plane of angle `theta_1` reaches the bottom in time `t_1`. The same block released from rest from the top of another smooth inclined plane of angle `theta_2` reaches the bottom in time `t_2` If the two inclined planes have the same height, the relation between `t_1 and t_2` isA. `t_2/t_1=((sin theta_1)/(sin theta_2))^(1//2)`B. `t_2/t_1=1`C. `t_2/t_1=(sin theta_1)/(sin theta_2)`D. `t_2/t_1 =(sin^2 theta_1)/(sin^2 theta_2)` |
| Answer» Correct Answer - C | |