A block rests on a rough inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between the block and the plane is 0.8. If the frictional force on the block is 10 N, the mass of the block ((in kg) is .......... (Take g = 10 m//s^(2))

A block rests on a rough inclined plane making an angle of 30° with t

1.	A block rests on a rough inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between the block and the plane is 0.8. If the frictional force on the block is 10 N, the mass of the block ((in kg) is .......... (Take g = 10 m//s^(2))
Answer» 2.0 kg 4.0 kg 1.6 kg 2.5 kg SOLUTION :Weightof a BLOCK `F= mg` The blockis atrest . Herewehavetakenfrictionalforce= Downwardcomponentof weightalonginclinedplane That is `f= mg sintheta:. ,m= (f )/( G sin theta )` Substituting`f= 10 Ng =10 :. , m = (10)/( 10 sin 30^(@))` But`sin theta= sin 30^(@)= (1)/(2)` we GETM =2kg