1.

A block slides down a rough inclined plane of slope angle theta with a constant velocity. It is then projected up the same plane with an initial velocity v. The distance travelled by the block up the plane before coming to rest is

Answer»

`(v^(2))/(4G sin theta)`
`(v^(2))/(2g sin theta)`
`(v^(2))/(g sin theta)`
`(4gv^(2))/(sin theta)`

Solution :`a_(d)=g(sin theta-mu_(k)COSTHETA)`
`a_(u)=g(sin theta+mu_(k)cos theta), v^(2)-u^(2)=2AS`


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