A block weighing 10kg is at rest on a horizontal table. The coefficient of static friction between the block and the table is 0.5. If a force acts downward at 60^(@) with the horizontal, how large can it be without causing the block to move ? (g=10ms^(-2))

A block weighing 10kg is at rest on a horizontal table. The coefficien

1.	A block weighing 10kg is at rest on a horizontal table. The coefficient of static friction between the block and the table is 0.5. If a force acts downward at 60^(@) with the horizontal, how large can it be without causing the block to move ? (g=10ms^(-2))
Answer» 346 N 446 N 746 N 846 N Solution :`F COS THETA=f, f=mu_(s)N, N=mg+F sin theta`