1.

A boat is moving in direction of vector -4hati+3hatj with a speed of 10 m/s. Velocity vector of boat can be expressed as :

Answer»

`-8hati+6hatj`
`-40hati+30hatj`
`-4/5hati+3/5hatj`
`-6hati+8hatj`

Solution :UNIT vector in the direction of velocity = U sin t cector along the given vector
`thereforehatv=(-4hati+3hatj)/(SQRT((4)^(2)+(2)^(2)))`
`vecv=|vecv|vecv=10((-4)/(5)hati+(3)/(5)hatj)=-8hati+6hatjm//s`


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