1.

A bob attached to one end of a string, other end of which is fixed at peg A. The bob is taken to a position where string makes an angle of to a position where string makes an angle of 30^@ with the horizontal. On the circular path of the bob in vertical plane there is a ped 'B' at a symmetrical position with respect to the position of release as shown in the figure. If V_(c) and V_(a) be the minimum speeds is clockwise and anticlock wise directions respectively, given to the bob in order to hit the ped 'B' then ratio V_(c) : V_(a) is equal to .

Answer»

`1 : 1`
` 1: sqrt(2)`
`1 : 2`
`1 : 4`

SOLUTION :For COMPLETE circular motion speed at HIGHEST point in `sqrt(gR)`
APPLYING CONSERVATION energy `v_(a) = sqrt(2gR)`
For clock wise motion
`T +mg cos 60 = (mv_(c)^(2))/(R)`
`v_(C)` to minimum `T=0 , v_(C) = sqrt((gR)/(2))`.


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