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A bob executes shm of period 20 s. Its velocity is found to be 0.05 ms^(-1)after 2 s when it has passed through its mean position. Find the amplitude of the bob. |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`T = 20 s, v=0.05 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1), t=2 s` <br/> `omega = (<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/T =2/20 pi = (pi)/10 rad//s` <br/> `v = aomega <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> omegat` <br/> `=0.05 = (api)/10 cos""(pi)/10 xx2 = (pia)/10 cos""pi/5` <br/> `0.05 = (pia)/10 xx0.809` <br/> `a= (0.05xx10)/(3.14 xx0.809)=0.197m`</body></html> | |