A body a starts from rest with an acceleration a_(1) . After 2s, another body B starts from rest with an accelerationa_(2). If they travel equal distances in the 5^(th)second after the start of A then, the ratio a_(1) :a_(2)is equal to :

A body a starts from rest with an acceleration a_(1) . After 2s, anoth

1.	A body a starts from rest with an acceleration a_(1) . After 2s, another body B starts from rest with an accelerationa_(2). If they travel equal distances in the 5^(th)second after the start of A then, the ratio a_(1) :a_(2)is equal to :
Answer» <html><body><p>` <a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a> : <a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>` <br/>`9 : 5` <br/>`5 : 7`<br/>`5 : 9`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`S_(n) = u +(a)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) (2n-1)`<br/>`S_(5^(th))(A) = S_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>^(th))(B)`<br/>`0 + (a_(1))/(2) [(2 xx5)=1] = 0 +(a_(2))/(2) [ (2xx3) - 1]`<br/>`(a_(1)xx9)/(2) = (a_(2) xx5)/(2)`<br/>`:. (a_(1))/(a_(2)) = (5)/(9)`<br/>`a_(1) :a_(2) = 5:9`</body></html>