1.

A body attains a height equal to the radius of the earth. The velocity of the body with which it was projected is

Answer»

`SQRT((GM)/(R))`
`sqrt((2GM)/(R))`
`sqrt((1)/(4)(GM)/(R))`
`sqrt((GM)/(2R))`

Solution :Applying conservation of mechanical energy we get,
`(1)/(2)mv^(2)=(mgh)/(1+h//R)`
Putting h = R, we get
`v=sqrt(GR)=sqrt((GM)/(R))`


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