1.

A body cools from 60^@C to 50^@C in 10 min of room If the room temperature is25^@ C and assuming Newton's cooling law holds good, the temperature of the body after 10 more minute.

Answer»

Solution :ACCORDING to newtons law ofcooling
` ( theta_2 - theta_1)/(t) = k [ (theta_2 + theta_1)/(2) - theta_0 ]`
` therefore (60 - 50)/(10)= k [ (60 + 50)/(2) - 25]`
` 1 = 30 k " or" k = 1/30`
` (50 - theta)/(10) = k [ (50 +theta)/(2) - 25 ] = k theta / 2 = (theta)/(60)`
or ` 70 theta =3000, theta = 300/7 = 42.8^@C`


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