A body covera `10 m` in the seconds second and `25 m` in finfth second of its motion. If the motion is uniformly accelerated, how farwill it go in the the seventh second?

A body covera `10 m` in the seconds second and `25 m` in finfth second

1.	A body covera `10 m` in the seconds second and `25 m` in finfth second of its motion. If the motion is uniformly accelerated, how farwill it go in the the seventh second?
Answer» `10=u+(a)/(2)(2xx2-1)` and `25=u+(a)/(2) (2xx5-1)` Solving, we get `u=(5)/(2)m s^(-1), a= ms^(-2)` `D_(7)=(5)/(2)+(5)/(2)[2xx7-1] =35 m`.

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A body covera `10 m` in the seconds second and `25 m` in finfth second of its motion. If the motion is uniformly accelerated, how farwill it go in the the seventh second?

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