Saved Bookmarks
| 1. |
A body covers 100cm in first 2 seconds and 128cm in the next four seconds moving with constant acceleration. Find the velocity of the body at the end of 8 sec? |
|
Answer» Solution :In first 2 seconds `100=2u+(1)/(2)a.4……(1)` In first 6 seconds `228=6u+(1)/(2)a.36rarr(2)` `(1)xx3-(2)" gives "72=-12a` `a=-6cm//s^(2)......(3)` `100=2u-(1)/(2)xx6xx4` `2u=112` `u=56cm//s......(4)` Now VELOCITY of body at the end of 8 SEC is `V=u+at=56-6xx8` `THEREFORE V=8cm//s`. |
|