1.

A body describes simple harmonic motion with an amplitude of 5 cm and a period of 0.2s. Find the acceleration and velocity of the body when the displacement is 5 cm.

Answer»

`(A)/(3)`
`(A)/(2)`
`(A)/(SQRT(2))`
`(A)/(2sqrt(2))`

SOLUTION :POTENTIAL energy = `(1)/(2)` (Total energy)
`(1)/(2)momega^(2)y^(2)=(1)/(2)((1)/(2)momega^(2)A^(2))impliesy=(A)/(sqrt(2))`


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