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A body dropped from the top of a tower falls through 40 m during the last 2 seconds of its fall then the height of the tower is |
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Answer» let the total time of fall of the body be t sec then In t sec it falls (1/2)gt2 and in t-2 sec it falls 1/2 g(t-2)2 so by the given condition (1/2)gt2 -1/2 g(t-2)2 =40 =>1/2g(t2-t2+2t-4)=40 =>10t-20=40 [ taking g=10m/s2] => t=6 sec Hence height of the tower H = 1/2x10x62 = 180m |
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