A body executes SHM such that its velocity at mzean position is 2m/s and acceleration at extreme position is 4m//s^2 Find the time period of the motion.

A body executes SHM such that its velocity at mzean position is 2m/s a

1.	A body executes SHM such that its velocity at mzean position is 2m/s and acceleration at extreme position is 4m//s^2 Find the time period of the motion.
Answer» Solution :At MEAN POSITION, velocity is MAXIMUM i.e., A`omega`= 2. Similarly at extreme position acceleration is maximum i.e. `A omega^2 = 4pi` from the above TWO relatives `w= 2pi ` c/s Time PERIOD `T= (2pi)/(omega) = (2pi)/(2pi)= 1s`