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A body executing S.H.M. has a period of 3 s under one force and 4 s under another force. Then time period under the action of both the forces together in the same direction isA. 1.2 sB. 2.4 sC. 3.6 sD. 4.8 s |
Answer» Correct Answer - B `T=(T_(1)T_(2))/(sqrt(T_(1)^(2)+T_(2)^(2)))=(3xx4)/(sqrt(9xx16))=(3xx4)/(5)` `=(12)/(5)=2.4s` |
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