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A body falls freely from a height of 125m(g=10m//s^(2)) after 2 sec gravity ceases to act Find the time taken by it to reach the ground?

Answer» <html><body><p></p>Solution :Distance covered in 2s under <a href="https://interviewquestions.tuteehub.com/tag/gravity-18707" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITY">GRAVITY</a> <br/> `s_(1)=(1)/(2)g t^(2)=(1)/(2)(10)2^(2)=<a href="https://interviewquestions.tuteehub.com/tag/20m-293046" style="font-weight:bold;" target="_blank" title="Click to know more about 20M">20M</a>` <br/> velocity at the end of 2s <br/> `V=g t=(10)2=20m//s`. <br/> Now at this instant gravity <a href="https://interviewquestions.tuteehub.com/tag/ceases-911108" style="font-weight:bold;" target="_blank" title="Click to know more about CEASES">CEASES</a> to act <br/> implies velocity by here after <a href="https://interviewquestions.tuteehub.com/tag/becomes-1994370" style="font-weight:bold;" target="_blank" title="Click to know more about BECOMES">BECOMES</a> constant. <br/> The remaining distance which is `125-20=105m` is covered by the body with constant velocity of `20m//s`. <br/> Time taken to cover `105m` with constant velocity is given by, <br/> `t_(1)=(S)/(V)impliest_(1)=(<a href="https://interviewquestions.tuteehub.com/tag/105-266496" style="font-weight:bold;" target="_blank" title="Click to know more about 105">105</a>)/(20)=5.25s` <br/> Hence total time taken to reach the ground <br/> `=2+5.25=7.25s`</body></html>


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