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InterviewSolution
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A body falls freely from a tower and travels a distance of 40 m in its last two seconds. The height of the tower is 1. 54 m 2. 45 m 3. 80 m4. 65 m |
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Answer» 2. 45 m \(\frac{1}{2}\)g (t)2 - \(\frac{1}{2}\)g (t - 2)2 = 40 ⇒ 5t2 - 5(t - 2)2 = 40 ⇒ t2 - (t - 2)2 = 8 ⇒ t = 3 ∴ height = \(\frac{1}{2}\)gt2 = \(\frac{1}{2}\) x 10 x 9 = 45 m. |
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