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A body floats in water with 40% of its volume outside water. When the same body floats in an oil. 60% of its volume remians outside oil. The relative density of oil isA. `0.9`B. `1.0`C. `1.2`D. `1.5` |
Answer» Correct Answer - D Using the law of buoyancy, we have `V sigmag=0.6 V sigma_(1)g`, for the part of body outside oil and `Vsigma_(2)g`, for the part of body outside water, hence we get `1=(0.6 sigma_(1))/(0.4 sigma_(2))` So, we have, `(sigma_(1))/(sigma_(2))=(6)/(4)=(3)/(2)=15` |
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