A body has a time of 3 s under the action of one force and 4 s under the action of another force. Calculate the time period when both the forces act in the same direction simultaneously. Assume that the body undergoes the same displacement, under the action of the two different forces.

A body has a time of 3 s under the action of one force and 4 s under t

1.	A body has a time of 3 s under the action of one force and 4 s under the action of another force. Calculate the time period when both the forces act in the same direction simultaneously. Assume that the body undergoes the same displacement, under the action of the two different forces.
Answer» SOLUTION :`F_1=momega^2y=momega^2(2pi//3)^2,F_2=momega^2(2pi//4)^2,F_1+F_(2)=(2pi//T)^2,1//T^2=1//3^2+1//4^2,T=2.4` SECOND.