1.

A body has maximum range R_(1) when projected up the inclined plane. The same body when projected down, the inclined plane. It has maximum range R_(2). Find its maximum horizontal range. Assume the equal speed of projection in each case and the body is projected onto the gretest slope.

Answer»

`R=(2R_(1)R_(2))/(R_(1)-R_(2))`
`R=(2R_(1)R_(2))/(R_(1)+R_(2)`
`R=(R_(1)R_(2))/(R_(1)-R_(2))`
`R=(4R_(1)R_(2))/(R_(1)+R_(2))`

Solution :For upward projecton, `R_("MAX")=(V_(0)^(2))/(g(1-sinbeta))=R_(1)` .............(i)
For downward PROJECTION `R_("MIN")=(v_(0)^(2))/(g(1+sin beta))=R_(2)` ..........(ii)


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