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A body is immersed in a liquid of relative density 2.6. It is found that the weight of the body in the liquid is two-thirds of its weight in air. Calculate the density of the body ? |
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Answer» Solution :Let `RHO` be the density of the body and `V_(1)` its volume, then according to Archimedes principle `V_(1)rho g-V_(1)rho_(1)g=(2)/(3)V_(1)rhog` `(rho_(1)`=density of the liquid) `THEREFORE V_(1)rho g-v_(1)rhog-(2)/(3)V_(1)rho g` `implies rho=3rho_(1)=3xx2.6xx10^(3) kg m^(-3)` `=7.8xx103 kg m^(-3)` Density of the body is `7.8xx103 kg m^(-3)` |
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