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A body is moving on a frictionless curved path of radius of 1.8 km with a speed of 30 ms-1. Find the banking angle required. |
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Answer» The centripetal force required to keep the body in circular motion is \(\frac{mv^2}{r}\) Here, v = 30 ms-1 r = \(\frac {1.8 \times 10^3m}{2}\) = 0.9 103 = 900m N cos θ = mg and \(\frac{mv^2}{r}\) = N sinθ \(\frac{mv^2}{r}\) = \(\frac{mg}{cos \theta}\) sinθ ⇒ tan θ = \(\frac {v^2}{rg}\) ⇒ θ = tan-1 \(\frac {30^2}{900 \times 10}\) ⇒ θ = tan-1 (0.1) = 5.71°. |
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